| Stream
Discharge |
| Lesson Abstract |
| Summary: |
Students will determine the amount of stream discharge
in
cubic feet per second. |
| MO GLE: |
SC4.1.D.6,5.1.A.6, 5.3.A.6, 7.1.A.6 |
| Subject Areas: |
Science, Mathematics |
| Show-Me |
Goal –1.6, 1.105 |
| Standards: |
Strands – SC 1, 4, 5, 7; MA 2 |
| Skills: |
Addition, subtraction, multiplication, division, measurement
of
width and depth |
| Duration: |
Field trip (2 hours in field) |
| Setting: |
Shallow stream (2 feet deep or less) |
| Key Vocabulary: |
Gradient, velocity, cubic feet per second (cfs), discharge |
Rationale:
- Students will apply mathematical concepts to real
life situations involving water usage.
Student relevance:
- The calculation of discharge is used to determine
the beneficial use of a stream.
- Streams may be useful as municipal water supplies
or for irrigation.
- Discharge calculations are also used for flood control
information and to determine the requirements for wastewater treatment
plants that discharge into streams.
- The amount of discharge of a stream affects its usage.
Learning Objectives:
Upon completion, students will be able to . . .
- Collect field data.
- Calculate the flow and cross-sectional area of a
stream.
- Determine the suitability of the stream water use
applications.
Students Need to Know:
- Addition, subtraction, and division.
- How to measure with a ruler.
- How to measure with a tape measure.
Teachers Need to Know:
- River/stream discharge has a direct impact on resource
use.
- How to calculate stream discharge.
- The volume of water flowing within a stream is called
stream discharge.
- Stream discharge is the product of the stream’s
mean velocity and its cross-sectional area.
- Prior to determining stream discharge, all stream
velocity and cross-sectional area measurements must be taken and all
calculations for velocity and cross-sectional area must be completed.
- Discharge is expressed in cubic feet of water flowing
past a given point along the stream per second, or simply cubic feet/second
(cfs).
- A cubic foot of water is equal to 7.48 gallons of
water. It can be represented as a container one foot wide, one foot
long, and one foot high.
- If the discharge of a stream is one cubic foot/second
(cfs), then 7.48 gallons of water flow past a point every second.
- Total gallons are often the most useful unit in explaining
discharge to a general audience.
- Calculation for discharge, in cfs, is determined
by cross-sectional area of stream multiplied by the mean velocity of
stream.
- Total gallons of discharge per second are determined
by the discharge, in cfs, multiplied by 7.48 gallons.
Resources:
The following are available from the Missouri Department
of Natural Resources, Division of Geology and Land Survey, P.O. Box 250,
Rolla, MO 65402, (573)368-2125.
Water Use of Missouri Water Resources Report No.
48 ($12 plus shipping)
Water Atlas of Missouri ($10 plus shipping)
The following are available at no charge from the Missouri
Department of Conservation, P.O. Box 180, Jefferson City, MO 65102-0180,
(573)751-4115.
Fishing for Answers: The Challenge of Conserving
Aquatic Resources, 1991
Fishing for Answers: Teacher’s Edition, 1991
Water Quality Monitoring Notebook, Level One (available with
volunteer water quality
training workshop)
Materials Needed for Lesson:
Field site consideration: water should be no more than
knee deep on students
100’ survey tape (50’ or 25’ will work)
Practice whiffle Golf Ball (plactic)
Measuring stick (measured in .1 foot increments) or a dowel rod marked
off in .1 foot
increments with a permanent marker
Stopwatch or watch with a second hand
Stream Discharge Activity (handout)
Procedure:
- Discuss the different sizes of rivers and how they
are used based on their size (for example, barge travel versus inner
tube travel).
- Using the Stream Discharge Activity handout, first
model the procedure for stream discharge in the classroom using hypothetical
measurements.
- Generate at least three fictional data sets and graph
the flows using the scientific inquiry method with the dependent and
independent variables.
- Then determine actual discharge at three points on
a designated field trip site.
Evaluation Strategies:
- Allow groups of students to measure flow and compare
results.
- Based on data collected and graph outcomes, write
a paragraph summarizing the results and then discuss appropriate and
inappropriate stream uses.
- Performance Task: You are the engineers for a new
dam. With the data you have determined in the activity (cfs), how long
would it take to fill a community lake? Determine the size (depth and
area) of the lake, then show and explain your calculations.
Extension Activities:
- Inventory stream usage within a local watershed.
Compare and contrast stream usage and discharges (or relative sizes).
- Compare stream flow discharge to that of other rivers
in Missouri using the Missouri Water Atlas or Water Use of Missouri.
Suggested Scoring Guide:
| |
Points
Points
|
Possible
Earned |
| 1. Statement of hypothesis |
10 |
|
| 2. Graph: |
|
|
a. Proper Title
|
10 |
|
b. Axes drawn and labeled
|
10 |
|
c. Dependent variable and units labeled
|
10 |
|
d. Independent variable and units labeled
|
10 |
|
e. Appropriate scale
|
10 |
|
| 3. Summary of Results |
10 |
|
| 4. Participation in discussions |
10 |
|
| 5. Stream Discharge Activity |
10 |
|
| 6. Performance Task |
10 |
|
| Total Points Possible |
100 |
|
Stream Discharge Activity
Directions: Follow the
steps below using the designated materials.
1. Measure and mark a 100-foot
distance along a straight section of the stream (if you
cannot find a straight 100-foot section, use 10’, 25’ or 50’).
2. Place an practice Whiffle
golf ball (or a stick 5-6” long) in the water at the upstream marker.
3. Record the number of seconds
it takes for the Whiffle ball to float between the stakes.
4. Divide the 100 feet (or 50 feet or 25 feet) by the number of seconds.
5. Do this three times and use
the average time.
1st 100 feet divided
by ¬¬_____ seconds = _____ feet/second
2nd 100 feet divided by ¬¬_____ seconds = _____ feet/second
3rd 100 feet divided
by ¬¬_____ seconds = _____ feet/second
Total _____ feet/second
divided by 3 = _____ feet/second Average
6. Find the average width of
the stream: Measure width of the stream at three places
within the 100-foot area, then divide the total by three to get the average
width.
7. Find the average depth of the
stream: Measure depth of the stream in three places
across the stream in a straight line, then divide the total by four to
get the average
depth of the stream.
_____ feet plus _____ feet plus
_____ feet = _____ divided by 3 = _____ feet
1st 2nd 3rd Total Average width
Note: The reason you take three
depth measurements and divide by four is to take
into account the shallow areas of the stream. For example, if depth in
three places
is A(.5’), B(.8’), and C(.5’, total (1.8’), average
depth is determined by dividing by 4:
1.8’/4=.45’, the correct average depth.
8. Find the cubic feet of water/second:
Multiply the average width, average depth, and
number of feet/second. A cubic foot is water in a container one foot wide
by one foot high by one foot long, or 7.48 gallons.
__________ feet x __________ feet
x __________ feet/second = __________ cfs
Ave. width Ave. depth Velocity Rate of flow
9. To determine total gallons,
multiply cfs by 7.48 gallons.
|